Edges, mn
So the degree sequence of Km,n consists of m n's and n m's listed in non-increasing order.
E connects every vertex in U with all vertices in V. It follows that Km,n has mn edges.
One reason for this is that if a vertex v is adjacent to x it cannot be adjacent to y since y and v would be in the same part. I would like to share my proof, please tell ...
The complete bipartite graph Km,n has exactly mn edges. Proof.
This is a permutation problem: there are 3! orders in which 1, 4 , 6 can
It is also perfect (since it is the line graph of a bipartite graph) and vertex -transitive. The n×n
Maximum is not the same as maximal: greedy will get to maximal.
This paper looks at complete n-partite graphs, Km1,m2,m3,...,mn . The main focus is to
Is there a bipartite graph with degree sequence (3,3,3,3,3,3,3,3,3,5,6,6,6)?